15min:
SPECTRAL DISSIMILARITIES BETWEEN AZULENE(C10H8) AND NAPHTHALENE(C10H8).

MASAAKI BABA, Graduate School of Science, Kyoto University, Sakyo-ku, Kyoto 606-8502, Japan.

Polycyclic aromatic hydrocarbons (PAHs) are of great interest in the molecular structure and excited-state dynamics, and there have been extensive spectroscopic and theoretical studies. Azulene and naphthalene are bicyclic aromatic hydrocarbons composed of odd- and even-membered rings, respectively. First, they were discriminated by a theory of mutual polarizability. Naphthalene is an alternant hydrocarbon, but azulene is not. In contrast, spectral resemblances were found by John Platt et al ., and were explained by their simple model of molecular orbital. However, the absorption and emission feature of the S1 and S2 states is completely different each other. We have investigated each rotational and vibrational structures, and radiative and nonradiative processes by means of high-resolution spectroscopy \footnoteY. Semba, M. Baba, et al. , J. Chem. Phys. , 131, 024303 (2009) \footnoteK. Yoshida, M. Baba, et al. , J. Chem. Phys. , 130, 194304 (2009) and ab initio calculation. The equilibrium structures in the S0, S1, and S2 states are similar. This small structural change upon electronic excitation is common to PAH molecules composed of six-membered rings. The fluorescence quantum yield is high because radiationless transitions such as intersystem crossing (ISC) to the triplet state and internal conversion (IC) to the S0 state are very slow in the S1 state. In contrast, the S1 state of azulene is nonfluorescent and the S1 leftarrow S0 excitation energy is abnormally small. We consider that the potential energy curve of a b2 vibration is shallower in the S1 state, and therefore the vibronic coupling with the S0 state is strong to enhance the IC process remarkably. This situation is, of course, due to its peculiar characteristics of odd-membered rings and molecular symmetry, which are completely different from the naphthalene molecule.